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2010-01-20 1問目

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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below 1000.

#include <iostream>
#include <time.h>

using namespace std;

int main()
{

	int n=0;
	for(int i=1;i<1000;i++){
		if(i%3==0||i%5==0){
		n=n+i;
		}
	}
	 cout<<n<<endl;

}